3x^2-12x+40=0

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Solution for 3x^2-12x+40=0 equation:


Simplifying
3x2 + -12x + 40 = 0

Reorder the terms:
40 + -12x + 3x2 = 0

Solving
40 + -12x + 3x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
3 the coefficient of the squared term: 

Divide each side by '3'.
13.33333333 + -4x + x2 = 0

Move the constant term to the right:

Add '-13.33333333' to each side of the equation.
13.33333333 + -4x + -13.33333333 + x2 = 0 + -13.33333333

Reorder the terms:
13.33333333 + -13.33333333 + -4x + x2 = 0 + -13.33333333

Combine like terms: 13.33333333 + -13.33333333 = 0.00000000
0.00000000 + -4x + x2 = 0 + -13.33333333
-4x + x2 = 0 + -13.33333333

Combine like terms: 0 + -13.33333333 = -13.33333333
-4x + x2 = -13.33333333

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -13.33333333 + 4

Reorder the terms:
4 + -4x + x2 = -13.33333333 + 4

Combine like terms: -13.33333333 + 4 = -9.33333333
4 + -4x + x2 = -9.33333333

Factor a perfect square on the left side:
(x + -2)(x + -2) = -9.33333333

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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